صفحه 1:
gure 1-7 | John Dalton (1766-1844), an Englishman, began teaching at a Quaker
school when he was 12. His fascination with scence Included an intense interest in meteo-
rology, which led to an interest in the gases of the air and their ultimate components,
atoms. Dalton عا best known for his atomic theory, in which he postulated that the funda
mental differences among atoms are thelr masses. He was the first to prepare a table of
relative atomic weights.
Dalton was @ humble man with several apparent disabilities: He was not articulate and he
was color-blind, a terrible problem for a chemist. Despite these disadvantages, he helped to
revolutionize the science of chemistry.
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Finnigan
صفحه 2:
نظریه اتمی دالتون
-در زمان دالتون می دانستند که آب از اکسیژن و هیدروژن تشکیل شده است و
به ازاء هر 8 گرم اکسیژن 1 گرم هیدروژن مصرف می شود.
-بثابراین بر پایه زاين فرمن که تطبیعت:جن:جد امکان:ساده
نت او جرم هیدروژن را 1 و جرم اکسیژن را 8 فرض
د.
-بر پایه همین استدلال برای ترکیب های دیگر اولین جدول
جرمهای اتمی را تهیه کرد.
-بعداً مشخص شد که جرمهای بسیاری از اتمها اشتباه
است اما تهیه اولین جدول جرمها یک مرحله به جلو بود.
-اگر چه تا سالها نظر دالتون پذیرفته نشد, اما کلید تعيين
فرمول مشخص ترکیبها با کار تجربی شیمیدان فرانسوی .
Gaylussac (1778-1850) وبا فرضیه یک
اه ایتاپبایی به نام )1776-1856( A. Avogadro
1۳020
صفحه 3:
نظریه اتمی دالتون
در سال 1809 گیلوساک آزمایش هایی انجام داد که در آنها او (در شرایط دما و
فشار یکسان) حجم گازهایی که با یکدیگر واکنش می دهند را اندازه گیری کرد.
<< در سال 1811 آووگادرو اين نتایج را اینگونه تفسیر کرد که
در یک دما و فشار, حجم های مساوی از گازهای مختلف
شامل همان تعداد ذره هستند.
< این فرض (که فرضیه آووگادرو نامیده شد) منطقی می
نمود اگر فاصله بین ذرات در یک گاز در مقایسه با اندازه
ذرات بسیار پیشتر باشد.
متأسفانه تفسیرهای آووگادرو مورد قبول اکثر شیمیدانهاواقع نشد. و نصف قرن
گیجی بر جامعه شیمیدانها حاکم بود که در آنها فرض های مختلفی برای توجیه
واقعیات ارائه می شد.
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Thermo Finnigan
صفحه 4:
اندازه گیری حجم گازها
«Joseph Louis Gay-Lussac a French plysicist and chemist, was remarkably versatile
though ets now known primarily forhis studies onthe combining of vlumes of gases,
a Lusacwas instrumental inthe tues of many ofthe other properties of gases Some
of Gay-Lusscs motivation to lear about gases arose from hs passin forbllooning.
Infact he made ascents to heights of over mils to collec air samples, setingaitude
records that stood fr about 50 years Gay-Lussac also was the codiscoverer of boron and
the developer af proces for manufacturing sufuic acid. Ascieassayer ofthe French
mint, Gay-Lussa developed many techniques fr chemical analysis ad invented many
‘ypescf glassware now used routine in abs, Gay Lussacspethis st 20 years sa
] government.
Thermo Finnigan
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فرضیه اووگادرو
volumes hydogen combines ۱ volume oxygen to form 2 volumes gaseous water
2.
| volume hydrogen combines with I volume chlorine to form 2 volumes hydrogen chide
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Thermo Finnigan
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نظریه اتمی دالتون
۶ در جریان قرن نوزدهم, اندازه گیری های دقیقی روی
عناصر مختلف انجام شد که منجر به ترکیبها
مختلف می شد. از.وی این آزمایشها لمستن از جرم
های اتمی نسبی می توانست بدست آید .
یکی از شیمیدانهای درگیردر این قضیه -1779) 3۲62611115 .[ .ل
(1848 بود که عناصر 51 ٩6, .6) و 1 را کشف کرد و سمبل های
جدیدی برای عناصر استفاده شده در نوشتن فرمول ترکیبها را توسعه داد
7 تمرین های 1 و 2 را حل کنید.
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Thermo Finnigan
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جرمهای اتمی برزیلیوس
The Alchemists! Symbols for Some
Common Elements and Compounds
۷
sts = ال
اه هو
Thermo Finnigan
صفحه 8:
آزمایشهای اولیه برای توصیف اتم
ظ اساس کار دالتون, گیلوساک, آووگادرو و سایرین شیمی
داشت احساس می شد! مفهوم اتمها کاملاً ایده خوبی
بود.
بدون تردید محققینی شروع کردند که به طبیعت اتمها
فکر کنند یک اتم از چه ساخته شده است و چگونه
اتمهای عناصر مختلف فرق دارند؟
۶ اولین آزمایشهای مهمی که منجر به درک اجزاء اتم شد
آزمایش محقق انگلیسی م۳ .لد بود.
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Thermo Finnigan
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Figure 1-10 | J.J. Thomson (1956-
1940) was an English physicist at
Cambridge University. He received
the Nobel Prize in physics in 1906.
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Finnigan
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لوله اشعه کاتدی
Sour of ltl oem
Siam of eating
penis (eaten)
. ‘cathode ray tbe. The fast moving electronseacit the gas inthe tube causing a
low between the electrodes. The geen color in the patois du tothe response of the screen (coated
with zinc sulfide to the electron beam.
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Thermo Finnigan
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| Deflection of cathode rays by an applied
electric field.
fears clon
where e represents the charge on the electron in coulombs (C) and m represents the
electron mass in grams.
Thermo Finnigan
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لوله اشعه کاتدی
> تامسون فرض کرد که تابش, جریانی از ذرات با بار منفی
می باشد که حالا آلکترون نامیده می شود.
۶ - او استدلال کرد که چون الکترونها می توانند از
الکترودهایی که از انواع فلزات تهیه می شوند. ساطع
شود لذا تمام اتمها باید دارای الکترون باشند.
* چون اتمها از لحاظ الکتریکی خنثی بودند تامسون فرض
کرد که اتمها ub دارای مقداری بار مثبت باشند.
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Thermo Finnigan
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Spherical cloud of
positive charge
StockFoxd/Goty images
4 Aclassic English plum pudding,
in which the raisins represent the
distribution of electrons in the atom. The plum pudding model of the atom.
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Thermo Finnigan
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در سل ۱۹۰۹ راپرت میلیکان (۱۹۵۲-۱۸۲۸) که در دنشگاه شیکاگو کار می کردآزمایشهای متهورانه ای انجام داد
و توانست مقدار پا لکترون را اداژهگیری کند.
1 هسیر
wos 3 595
دده اا لله
۳ اعم Mion
مس
ماس
hee
@)A schematic representation ofthe apparatus Millikan used to determine the
<charge.on the electron. The fll of charged oll droplets due to gravity can be halted by adjusting the
voltage across tha two plates. This voltage andthe mass ofthe oll drop can then be uted to calculate
‘the charge on the of drop. milikan’s experiments showed that the charge on an oll drop is aways
‘hiole-number multiple ofthe electron charge. (b) Robert Milikan using his apparatus.
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Thermo Finnigan
صفحه 15:
0 م
et ete Td
»
X-rays knock ۱
x
Cea
وین
Bote coy
Cena ee
Prete
me 7 0
م1 متقدمك مامتومه 00د ممنادجس كمومه معجة بوررعوقه 9
صفحه 16:
In 1909, the American physicist Robert Millikan (1868-1953) measured the
charge of the electron. He did so by observing the movement of tiny droplets of
the “highest grade clock oil” in an apparatus that contained electrically charged
plates and an x-ray source (Figure 2.5. next page). X-rays knocked electrons from
gas molecules in the air, and as an oil droplet fell through a hole in the positive
(upper) plate, the electrons stuck to the drop. giving it a negative charge. With the
electric field off. Millikan measured the mass of the droplet from its rate of fall. By
fuming on the field and varying its strength. he could make the drop fall more
slowly, rise, or pause suspended. From these data, Millikan calculated the total
charge of the droplet.
‘After studying many droplets, Millikan calculated that the various charges of
the droplets were always some whole-number multiple of a minimum charge. He
reasoned that different oil droplets picked up different numbers of electrons. so
this minimum charge must be that of the electron itself. The value. which he cal-
culated around 100 years ago. is within 1% of the modern value of the electron’s
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Thermo Finnigan
صفحه 17:
۱ for coulomb, the ST unit of charge). Using
the electron’s mass/charge ratio from work by Thomson and others and this value
for the electron’s charge. let’s calculate the electron’s exiremely small mass the
way Millikan did:
mass
—1.602x10~"e)
Mass of electron charge = (-s 686x10~
6
charge
= 9.109K 107 kg = 9.109x10-78 g
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Thermo Finnigan
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۶ در اواخر قرن نوزدهم محققین علوم کشف کردند که بعضی
عناصر تابش های پرانرژی تولید می کنند. برای مثال در سال
6 محقق فرانسوی اسسحب9) .1 بطور تصادفی کشف
کرد که یک قطعه سنگ معدن حاوی اورانیم می تواند تصویرش
را روی صفحه عکاسی در عدم حضور نور ظاهر کند.
۶ او اين پدیده را به یک بشر تابش خودبخودی توسط اورانیم
نسبت داد که او آن را رادیو اکتیونیه نامید.
۶ مطالعات اوایل قرن بیستم سه نوع بشر رادیو را نشان دادند:
۲ تابش گاما (۷) , ذرات بتا ( 8) و ذرات آلفا (0)
۶ یک LU gin "نور" پرانرژی است؛ یک ذره 8 یک الکترون پر
سرعت می باشد؛ و یک ذره 0 دارای بار +2 می باشد.
ظ جرم یک ذره 0,۳60 برابر جرم یک الکترون می باشد.
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Thermo Finnigan
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Ernest Rutherford
(1871-1937) was born ona farm in New
Zealand. In 1895 he placed second ina
scholarship competition to attend
Cambridge University but was
awarded the scholarship when the
winner decided to stay home and get
married. As a scientist in England,
Rutherford did much of the early work
on characterizing radioactivity. He
named the a and f particles and the
yay and coined the term haff-ife to
describe an important attribute of
radioactive elements. His experiments
on the behavior of a particles striking
thin metal foils led him to postulate
the nuclear atom. He also invented the
name proton for the nucleus of the
hydrogen atom. He received the Nobel
Prize in chemistry in 1908.
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Finnigan
صفحه 20:
Some at particles Most particles
ae scattered pass straight
through fil
Source of Beam of
particles
Screen to detect Thin
seatiered particles metal fil
Rutherford’s experiment on a:partcle bombardment of metal fil
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Thermo Finnigan
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۳ Diffuse
o
The expected results ofthe metal fil ‘Actual results,
‘experiment sf Thomson’ mode! were correct.
(a) The expected
results of the metal foil experiment
if Thomson's model were correct.
(b) Actual results,
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Thermo Finnigan
صفحه 22:
نگاه جدید به ساختار اتم
۶ در فکر راترفورد اين نتلیج تنها می توانست برحسب یک
هسته اتمی توضیح داده شود.
< ساده ترین تصویر از انم cowl gal که آن شامل یک
هسته کوچک (پا قطر حدود 12*10 سج) و الکترونها که در
اطراف هسته با یک فاصله تقریبی 10* «ماز آن حرکت
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Thermo Finnigan
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نگاه جدید به ساختار اتم
‘Nucleus
‘The Mass and Charge of the Electron,
Proton, and Neutron
“10% om
Electron 9.109 x 10" Ig 1
Proton 1.673 x 10-7 kg. 1+
| Neutron 1675 x 107 kg None 0
*The magnitude ofthe charge ofthe electron and the protons
160x10-%C. Anuclear atom
viewed in cross section, Note that this
drawing isnot to scale.
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Thermo Finnigan
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نگاه جدید به ساختار اتم
If the atomic nucleus were the size
of this ball bearing, a typical atom
would be the size of this stadium.
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Finnigan
صفحه 25:
نگاه جدید به ساختار اتم
۶ همانطور که در آینده نشان خواهیم داد شیمی یک انم
عمدتا ناشی از الکترونهای آن می باشد. به همین دلیل می
توان با یک مدل هسته ای نسبتاً نیم بند هم دل پست.
* فرض می شود که هسته شامل پروتونها که یک باز مصبت
مساوى با بار منفى الكترون دارند و نوترونها كه اساسا
جرمى برابر با يروتون داوند ولى بان ندارند.
<< دانسيته بسيار زياد هسته را مى توان اينكونه تعريف كرد
كه در حقيقت يى قطعه از هسته ماده با اندازه حدود يى
يسته جرمى در حدود 25 ميليون تن دارد.
> سئوالی که در اینجا می توان مطرح کرد این است که اگر
تمام اتمها از چنین اجزايي درست شده اند چرا اتمهای
مختلف خواص شیمیایی متفاوتی دارند؟
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Thermo Finnigan
صفحه 26:
ظ جواب به این سئوال به تعداد و آرایش الکترونها تکیه دارد.
۶ الکترونها عمده حجم rail را تشکیل می دهند و به همین دلیل
آنها آن قسمتهائی هستند که وقتی اتمها برای تشکیل مولکولها
به هم تردیکبهی نوتجا تگدرگن "ورمی آمیرته۱۳
> بنابراین تعداد الکترونهائی که یک pil دارد شدیدا روی توانائی
ol برای کنش با اتمهای دیگر تاثیر می گذارد
۶ در نتیجه, اتمهای عناصر مختلف, که دارای تعداد متفاوتی
پروتون و الکترون هستند رفتار شیمیائی متفاوتی نشان می
دهند.
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Thermo Finnigan
صفحه 27:
۵ where the alomde number 7 (numer of proton) i weten aca scrip, andthe
umber iggggy لوقصم سمو (he totl numberof pots and عر ستيه عد ماشه ع ميمه
siete Soe, Phe particu sto represented heres called “Schum twenty thr” I hes 11 ole
اه
trons 1 protons and 12 neutrons) <@ Beceuse the chemistry ofan atom ide 1
وا ی
سح
و
3 سس
aN fiNa
Two sotopesof
sau. doth have M protons a
‘elecwors, butte fern the
‘number ofreetion nthe mace
Thermo Finnigan
صفحه 28:
An atom of uranium-235
28
Thermo Finnigan
Co 0
+>م52
12600
An atom of uranium-238
صفحه 29:
روش علمی
Neutral sodium
atom (Na)
Sodium ion
(Na*)
1+ ——Minus | electron —> ۱۱+
1electrons
1 electrons
Na —> Na’ +e
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Thermo Finnigan
صفحه 30:
Chloride ion
5
Neutral chlorine
atom (Cl)
lus | electron——>
17 electrons
18 electrons
حون جبب +
Thermo Finnigan
صفحه 31:
ایزوتویهای عناصر و طیف سنج جرمی
@ ttre rete
سس
عم مه ماع 5
jo
و
۱ و
وس و
000
md magne gon
a
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Thermo Finnigan
صفحه 32:
جرم اتمى عناصر
۶ اجازه دهید ببینیم چگونه از داده های بدست آمده
ازدستگاه طیف سنج جرمی اطلاعات کلیدی بگیریم.
يا استفادة از ُکتوستگاه ظیفنتیج بچرمی ها capi
جرمی مثلا 000 را نسبت به 400 به دست آوریم.
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Thermo Finnigan
صفحه 33:
جرم اتمى عناصر
Mass of اه زج 534443
Mass of 5C standard
From this mass ratio, we find the isotopic mass of the **Si atom, the mass of the
isotope relative to the mass of the standard carbon-12 isotope:
Teotopic mass of Si = measured mass ratio % mass of 136
= 2.331411 x 12 amu = 2797693 amu
Along with the isotopic mass, the mass spectrometer gives the relative abun-
dance (fraction) of each isotope in a sample of the element. For example, the per~
cent abundance of “Si is 92.23%, Such data allow us to calculate the atomic
mass (also called a‘omic weight) of an element, the average of the masses of its
namrally occurring isotopes Weighted according to their abundances.
Each naturally occurring isotope of an element contributes a certain portion
to the atomic mass, For instance. as just noted, 92.23% of Si atoms are “*Si, Using
this percent abundance as a fraction and multiplying by the isotopic mass of **Si
gives the portion of the atomic mass of Si contributed by 7*Si
Portion of Si atomic mass from 7*Si = 27.97603 anu: x 0.9223 = 25.8031 am
Getaining nwo additional significant figures)
Similar calculations give the pertions contributed by “Si (28.976495 amu x
0.0467 = 1.3532 amu) and by *°Si (29.973770 amu X 0.0310 = 0.9292 amu),
and adding the three portions together (rounding to two decimal places at the end)
gives the atomic mass of silicon
$031 amu + 1.3532 amu + 0.9292 amu
28.0855 amu = 26.09 amu
Atomic mass of Si =
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Thermo Finnigan
صفحه 34:
جرم اتمى میانگین
FERED cect aici fn Ene
Problem Ses (Ag: 2» 4) bs 4 kaon topes bit oly v0 oer atl Way
sol ™Ag Gina te filloving ns spectonere dt, eal th stoi mus ofA
Massjamu) Abundance) مووایا
yy 19690809 su
Way 189075 4816
Plan Frm he mas and shane ofthe reo Agitopes, we lve to find the atomic هم |
aus of Ag (veined serge ofthe نومه ass). We rmply اوه توس نم
is aia sundae to fad he pote ofthe tne as cotibud by ech 5 مه هو بوي
ge Th ante prowi eabs شرس اف
Sabin Fig prt of edie msn eho:
بيه ممم سور
Ro eee لطم |
> 10590509 )ا ناضة 05184 * 5542 aaa 5
ite poe
Poria of aomis as fa "A: = 1059076 amu x 0-816 = 32.48 ann oo)
Finding the atemis mass of silver:
‘Atom mass, |
اه مه معط Ag = $542 ami + S245 amu = 10787ame
Thermo Finnigan
صفحه 35:
تعیین ترکیب در صد ایزوتویی
FOLLOW-UP PROBLEM 25 Boron (B: 2 = 5) bas to naturally occuring isotopes
Find the percent abundances of لو و زا the atomic mass of B = 10.81 amu,
tito ms of"3 = 10129 amu, andthe tos mss of B= 110983 am,
(Hint: The sum of the fractional abundances is 1, If x = abundance of then
1-1 = abmdance of روا
35
Thermo Finnigan
صفحه 36:
اولین نگاه به جدول تناوبی
36
Thermo Finnigan
صفحه 37:
The overwhelming majority of elements occur in chemical combination with
other elements. In fact, only a few elements occur free in nature. The noble
gases—helium (He), neon (Ne), argon (Az), krypton (Kr), xenon (Xe), and radon
(Rn)—ocour in air as separate atoms. In addition to occurring in compounds.
oxygen (©). nitrogen (N), and sulfur (8) occur in the most common elemental
form as the molecules O3, Nz, and Ss, and carbon (C) occurs in vast, nearly
pure deposits of coal. Some of the metals. such as copper (Cu). silver (Ag).
gold (Au), and platinum (Pt), may also occur uncombined with other elements,
But these few exceptions reinforce the general rule that elements occur coms
bined in compounds.
It is the electrons of the atoms of interacting elements that are involved in
compound formation. Elements combine in two general ways:
1, Transferring electrons from the atoms of one element to those of another 0
form ionic compounds (Figure 2.11)
2, Sharing electrons between atoms of different elements to form cova-
lent compounds
These processes generate chemical bonds, the forces that hold the atoms of ele-
ments together in a compound. We'll introduce compound formation next and
have much more to say about it in later chapters,
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Thermo Finnigan
صفحه 38:
قدرت پیوند يونى
2s
Attraction increas@silll) =
lee هو
Factors that influence the
strenath of ionic bonding. For jons of a
given size, strength of attraction (errows)
Increases with higher ionic charge (left 10
ight). For tons of a given charge, strength
Of attraction increases with smaller ionic
size (bottom to top).
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Thermo Finnigan
صفحه 39:
۱5۸/۸۳۱۴ ۲8۵۵۱۱ 2 Predicting the lon an Element Forms
Problem What monatomic ions do the following elements form?
(@) Iodine (Z = 53) (b) Calcium (Z= 20) (©) Aluminum (2 = 13)
Plan We use the given Z value to find the element in the periodic table and see whether
an clement loses or gains electrons to attain the same number as the nearest noble gas.
Elements in Groups 1A, 2A, and 3A lose electrons and become positive ions: those in
Groups $A, 6A. and 7A gain clections and become negative ions.
Solution (a) I~ Iodine (331) is a nonmetal in Group 7A(17), one of the helogens. Like
ay member of this group, it gains 1 eleciron to have the same number as the nearest Group
8A(18) member, in this case s4Xe.
(b) Ca’? Calcium (29C2) is a member of Group 2A(2). the alkaline earth metals. Like
any Group 2A member, it loses 2 electrons to attain the same number as the nearest noble
كمع in this case, ypAr
(©) AP* Aluminum (,341) is a metal in the boron family [Group 34(13)] and thus loses
3 electrons to attain the same number as its nearest noble gas, y9Ne.
FOLLOW-UP PROBLEM 2.6 What monatomic ion does each of the following elements
form: (a) 16S: (b) 37Rb; (¢) ssBa?
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تشکیل یک پیوند کووالانسی
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1۸ 2۸ 3A 4A 5A 6۸ 7۸ ۸۵
a) 2 (13) (14) (15) (16) (17) (18)
‘i
Diatomic molecules
8 Tetratomic molecules ?
1 octatomic molecules 3 P, | Ss
4 Seg
5
6
7
Elements that occur as molecules.
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کووالانس دارد
صفحه 43:
انواع فرمولهای شیمیائتی
Types of Chemical Formulas
Ina chemical formula, element symbols and numerical subscripts show the type
and number of each atom present in the smallest unit of the substance. There are
several types of chemical formulas for a compound:
1, The empirical formula shows the relative number of atoms of each element in
the compound. It is the simplest type of formula and is derived from the masses
of the component elements. For example. in hydrogen peroxide. there is 1 part
by mass of hydrogen for every 16 parts by mass of oxygen. Therefore, the
empirical formula of hydrogen peroxide is HO: one H atom for every O atom.
2. The molecular formula shows the actua/ number of atoms of each element in
a molecule of the compound. The molecular formula of hydrogen peroxide is
HO); there are two H atoms and two O atoms in each molecule.
A structural formula shows the number of atoms and the bonds benveen then;
that is, the relative placement and connections of atoms in the molecule. The
structural formula of hydrogen peroxide is H-O—O—H; each H is bonded
to an O, and the O's ate bonded to each other
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نام و فرمول ترکیبهای wig
‘Common Monatomic
tons*
Charge Formula. Name
Anions
Cations 8 ۲
9 5 a hydride
te tien 0
Nat vn a chloride
Ke cal bromide
00 tm iodide
ید silver 2 Sais
ea sulfide
oF Mg* magnesium
Cat calcium حي nitride
= an “Listed by charge; those in bolatace
a aa ‘are most common.
27 zine
oe كنات
3+ art aluminum
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Neng ay bn Conga
Problem Name the ionic compound formed trom the following pairs of elements:
(a) Magnesium and nitrogen (b) Iodine and cadmium
(©) Strontium and fluorine (@ Sulfur and cesium
Plan The key to naming a binary ionic compound is to recognize winch element is the
‘metal and which isthe nonmetal. When in doubt, check the periodic table. We place the
cation name first add the sufix ide to the nonmetal root, and place the anion name las.
Solution (a) Magnesium is the metal: mir- is the nonmetal :امم magnesium nitride
(b) Cadmium is the metal; iad- is the nonmetal root: cadmium iodide
(©) Strontium is the metal: fuor- is the nonmetal root: strontium fuoride (Note the
spelling is fluoride, not flouride,)
(@) Cesium is the metal: suf is the nonmetal root: cesium sulfide
FOLLOW-UP PROBLEM 2.7 For the following ionic compounds. give the name and
table group number of cach of the elements present: (a) zine oxide; (b) silver
bromide: (¢) lithium chloride; (d) aluminum sulfide
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= عم مر موی و of sont a
x Nae goup sone sat nero br, Rte th | da |
Bal ده بلس goer fee ow win bo ene cho
5 اناد سناد سيلب بابسا که موه موی
2 | anon Hin Gop TAL} Many transition evens fore we | SA] A | SR] A
Geert need om Otto Hay” Gro en. it 9
| دين smparnen wine
2
| 5 ِ ِ 5
1 | | كد | 5 |] 51 5] ] © | 2 jae
شلدات 5 سلثلة قاقفة
1
10 ۱
«| it Tat ۷ 20
3 Fe" | و cut 1
| 1 1
‘sn
۱۳" 1۳
1 i= sat?
| 2
ie رو |e
‘ea Bae |e Pot
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lonic Compounds رهوگ ه جمنجمه وه رم
Problem Write empirical formulas for the compounds named in Sample Problem 27.
Plan We write the empirical formula by finding the smallest number of each ion that gives
the neutral compound. These numbers appear as right subscripts to the element symbol.
Solution
(a) Mg?* and N? three Mg”* ions (6+) balance two N?~ ions (6-}: MgyNo
(b) Ca?* and I”; one Cd?* ion (2+) balances two I” ions (2-): Cdly
] and F>: one Sr°* ion (2+) balances two F> ions (2=): SiFy
(@ Cs* and S?>; two Cs* ions (2+) balance one 52 CS
“Compounds of the mercun() fon, such as Ha.Cl,, and peroxides of the alkal metals, such
‘as NazOz, are the only two common exceptions. Their empirical formulas are HgCl and
NeO, respectively,
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یونهای چند ظرفیتی
Some Metals That Form More Than One Monatomic lon’
Element lon Formula Systematic Name Common (Trivial) Name
Chromium cet hromium(II) ‘hromous
crt chromium(III) chromic
Cobalt Cot cobalt(II)
Cort cobalt(II)
Copper cat copper(l) ccuprous
crt copper(II) cupric
Tron Fe* iron(II) ferrous
Fe* iroa(II) fenic
Lead Pb?* ۱۸۵0
“كرا ۱۷/7
Mercury "جوا mercury(I) mercurous
Hg" mercury(I) mercuric
Tia sat tin(ll) stannous
“كبرو tin dV) stannic
“Listed alphabetically by metal rame; those in boldface are most common,
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Determining Nomes end Formulas of lnc Compounds
‘of Elements That Form More Than One lon
Problem Give the systematic names for the formmules or the formulas for the names of the
following compounds: (a, اس Buoride; (b) Cel: (€) ferric oxide: (@) CoS.
Solution (a) Tin(Il) is Su*"; fluoride is F. Two F ions balance one Sa’ ion: tin(I!)
Buoride is SuF2 (The common name is stannous fluoride.)
(b) The anion is I”, iodide, and the formula shows three I~. Therefore, the cation must
be Cr’*, chromium(III): Crls is chromiumn(Ilt) iodide, (The common name مم كذ
mic iodide.)
(© Femric is the common name for iron(II). Fe?*; oxide ion is O°. To balance the ionic
charges, the formula of feric oxide is Fe Oy, [The systematic name is iron(l) oxide]
(@) The anion is sulfide, S*-, which requires that the cation be Co". The name is
‘sobali() sulfide,
FOLLOW-UP PROBLEM 2.9 Give the systematic names for the formulas or the for-
rmulas for the names of the following compounds: (a) lead(IV) oxide; (b) CusS: (¢) FeBry
(@) meremtie chloride
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اکسی آنیونها
Families of Oxoanions most polyatomic ions are oxo:
ions, those in which an element. usually a nonmetal. is bonded to one or more
oxygen atoms. There are several families of two or four oxoanions that differ
only in the number of oxygen atoms. The following simple naming convention is
used with these ions.
With two oxoanions in the family:
+ The ion with more O atoms takes the nonmetal root and the suffix -ave.
+ The ion with fewer O atoms takes the nonmetal root and the suffix -re.
For example, $0,2~ is the sulfare ion; SOx
is nitrare, and NO> is nitrite.
With four oxoanions in the family (usually a halogen bonded to varying سه
bers of O atoms). as Figure 2.17 shows
~ is the sulfite ion; similarly, NOs
+ The ion with most O atoms has the prefix per-. the nonmetal root. and the
sufix -are.
+ The ion with one fewer © atom has just the root and the suffix -are.
+ The ion with nvo fewer 0 atoms has just the root and the suffix -ite
+ The ion with least (three fewer) O atoms has the prefix /iyo-, the root, and
the suffix -ite
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یونهای پلی اتمی
For example, for the four chlorine oxoanions.
ClO, is perehlorare. C103” is chlorate. CIOs is chlorite. CIO™ is Iypochlone
Common Polyatomic
Tons"
Nee
chromate همه
ند هو
peronide
Phosphate
acetate و
imei
هه مس
phosphate اه
igpeceoe ۳
ات
chlorate idrogen sulfate
pane ‘or biel)
هه ها ad
تس
مس
عدم
‘carbonate (or
bicarbonate)
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ترکیبهای یونی هیدراته
Hydrated lonic Compounds Ionic compounds called hydrates have a specific
number of water molecules associated with each formula unit. In their formulas,
this number is shown after a centered dot. It is indicated in the systematic name
by a Greek numerical prefix before the word /iydrare. Table 2.6 on the next page
shows these prefixes. For example. Epsom salt has the formula MgS0,-7H,0 and
the name magnesium sulfate /eptahydate. Similarly, the mineral gypsum has the
formula CaSO,:2H,0 and the name calcium sulfate dihydrate. The water molecules,
referred to as “waters of hydration.” are part of the hydrate’s structure, Heating can
remove some or all of them, leading to a different substance. For example, when
heated strongly, blue copper(II) sulfate pentahydrate (CuSO,°5H,O) is converted to
white copper(II) sulfate (CuSO,).
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ا م 2۰۱0 ۲۱۵۵۶۱۷ 5۸۷/۳۱۶
Containing Polyatomic lons
Problem Give the systematic names for the formulas or the formulas for the names of the
وس بو
م۵۳ —(b) Sodium sulfite —_(¢) Ba(OH),$H,0 .
Solution (a) ClO4~ is perchlorate, which has a 1— charge, so the cation must be Fe?*.
The name is iron(II) perchlorate. (The common name is ferrous perchlorate.)
(b) Sodium is Na*; sulfite is $07”. Therefore, two Na* ions balance one $03?> ion.
The formula is Nay$O3. (c) Ba”® is barium; OH” is hydroxide. There are eight (octa-)
water molecules in each formule unit. The name is barium hydroxide octahydrate.
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< تمرینها 3و 4:
FOLLOW-UP PROBLEM 2.10 Give the systematic names for the formulas or the formu-
las for the names of the following compounds:
(a) Cupric nitrate trihydrate (b) Zine hydroxide ۲
Ete) JUALIN Recognizing Incorrect Names and Formulas
of lonic Compounds
Problem Something is wrong with the second part of each statement. Provide the correct
name or formula.
(a) Ba(C3H303)) is called barium diacetate
(b) Sodium sulfide has the formula (Na)3SO3.
(©) Iron(II) sulfate has the formula Fe,(SOq)3.
(@) Cesium carbonate has the formula Cs,(CO,).
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Solution (a) The charge of the Ba** ion nmst be balanced by nvo C3Hy0,~ ions. so the
prefix di- is unnecessary. For ionic compounds, we do not indicate the number of ions
with numerical prefixes. The comect name is barium acetate.
(b) Two mistakes occur here. The sodium ion is monatomic, so it does not require paren
theses. The sulfide ion is S*-, not SO,” (called “sulfite”), The correct formula is NaS.
(©) The Roman numeral refers to the charge of the ion, not the number of ions in the for-
mula. Fe** is the cation, so it requires one $O,°- to balance its charge. The correct for-
mula is FeSOy.
(a) Parentheses are not required when only one polyatomic ion of a kind is present. The
correct formule is CsCOs.
FOLLOW-UP PROBLEM 2.11 State why the second part of each statement is incorrect,
and correct it:
(a) Ammonium phosphate is (NH3)4PO4.
(b) Aluminum hydroxide is AIOH3.
(©) Mg(HCO3); is manganese(IT) carbonate.
(d) Cr(NO3)3 is chromic(II1) nitride.
(e) Ca(NO>)> is cadmium nitrate.
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Acid Names from Anion Names Acids are an important group of hydrogen-
containing compounds that have been used in chemical reactions for centuries. In
the laboratory, acids are typically used in water solution. When naming them and
wiriting their formulas, we consider them as anions connected to the number of
hydrogen ions (H™) needed for charge neutrality. The two common types of acids
are binary acids and oxoacids:
1. Binary acid solutions form when certain gaseous compounds dissolve in
water. For example. when gaseous hydrogen chloride (HCI) dissolves in water.
it forms a solution whose name consists of the following parts
Prefix hydro- + nonmetal root + suffix -ic + separate word acid
hydro + chlor = + ie + acid
ot hydrochloric acid. This naming pattem holds for many compounds in which
hydrogen combines with an anion that has an -ide suffix,
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2. Oxoacid names are similar to those of the oxoanions. except for two suf-
fix changes:
+ -ate in the anion becomes -ic in the acid
٠ -ite in the anion becomes -ous in the acid
The oxoanion prefixes /npo- and per- are kept. Thus,
BrO,” is perbromate, and HBr04 is perbromic acid
JO) is iodite, and HIO) is iodous acid
۱۸۸۱۲۱۶ ۴8۵۵۱۶۸۷ SPM Determining Names and Formulas
of Anions and Acids
Problem Name the following anions and give the names and formulas of the acids derive
from them: (a) Br: (b) 103: (c) CN: (a) SOq?: () NO>.
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Solution (a) The anion is bromide; the acid is hydrobromic acid, HBr.
(b) The anion is iodate: the acid is indie acid, HIO,
(©) The anion is cyanide: the acid is _hydrocyanic acid, HCN.
(@) The anion is sulfate: the acid is sulfuric acid, HySOs. (In this case, the suffix is
added to the element name sulfia; not to the root, sulf-.)
(© The anion is nittite; the acid is nitrous acid, HNO
Comment We added tro H* ions to the sulfate ion to obtain sulfuric acid because it has
a 2— charge
FOLLOW-UP PROBLEM 2.12 Write the formula for the name or name for the formula
each acid: (a) chloric acid; (b) HF: (c) acetic acid: (d) sulfurous acid: (e) HBrO.
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Names and Formulas of Binary Covalent Compounds
Binary covalent compounds are formed by the combination of two elements.
usually noumetals, Several are so familiar, such as ammonia (NH), methane
(CHL), and water (HO). that we use their common names, but most are named
in a systematic way
1. The element with the lower group number in the periodic table is the first word
in the name; the element with the higher group number is the second word.
(Exception: When the compound contains oxygen and any of the halogens
chlorine, bromine, and iodine, the halogen is named frst.)
. If both elements are in the same group, the one with the higher period num-
ber is named first
. The second element is named with its root and the suffix -ide.
. Covalent compounds have Greek numerical prefixes (see Table 2.6) to indicate
the number of atoms of each element in the compound. The first word has a
prefix only when more than one atom of the element is present: the second
word usually has a numerical prefi.
5
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